A relation is in BCNF if for every non-trivial FD X → Y, X is a?
A relation is in BCNF if for every non-trivial FD X → Y, X is a?
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Answer
Super Key
Theory
BCNF is a stricter form of 3NF; every determinant must be a super key.
Solution
By definition of BCNF: X must be a super key.